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## Homework Statement

An electric motor draws 20.0 A of current when first switched on. The motors windings have a resistance of 5.0 ohm. Once the motor is up to full speed it draws only 4.4 A of current. Calculate the counter emf generated in the motor at full speed

## Homework Equations

I = V/R

V=IR

## The Attempt at a Solution

R = 5.0 ohm

A1 = 20.0 A

A2= 4.4 A n

1. (20A)(5.0ohm) = 100 V

2. (4.4A)(5.0ohm) = 22V

3. 100V - 22V = 78V

Im told im missing some "change", however I think this is correct, it is change in voltage?